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A #10 cm^3# volume of concentrated hydrochloric acid of density 1.18 g/#cm^3# and purity of 36 percent dissolved in #250 cm^3# of distilled water. Calculate the morality of the solution. (H = 1, Cl = 35.5)

Answer Text:
Mass of HCl in #10cm^3# = #10 times 1.18 times 36/100 = 4.248g#
Moles of HCl in #10cm^3# = #4.248/36.5 = 0.1164#
Molarity HCl in #250 cm^3# solution = #0.1164/0.25 = 0.4656 M#